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3 years ago

7 times as much as the sum of 1/3 and 4/5

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

5 0

First we need to make the fractions "compatible" for adding them easily, we can do that by equating their denominators using the common minimum multiple of their denominators 3 and 5 which is 15, so we have to multiply and divide to not modify them for a correct number, lets show that up:
1/3 = (5/5)(1/3) = 5*1/5*3 = 5/15, therefore: 1/3 = 5/15
4/5 = (3/3)(4/5) = 3*4/3*5 = 12/15, therefore 4/5 = 12/15
now we do the sum first:
<span>1/3 + 4/5
</span>= 5/15 + <span>12/15
= 17/15
and finally we multiply by 7
7*(</span><span>17/15</span>) = 119/15

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butalik [34]

<h2>Answer:</h2> $10.\text{ Option B is correct}$

<h2>Explanation:</h2>

Given the equation expressed as:

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First, we need to calculate the value of "x" from the given expression.

Step 1: Given the equation 2x + 5 = 8x

Step 2: Subtract 5 from both sides:

$\begin{gathered} 2x+5-5=8x-5 \\ 2x+\cancel{5}-\cancel{5}=8x-5 \\ 2x=8x-5 \end{gathered}$

Step 3: Subtract 8x from both sides

$\begin{gathered} 2x-8x=8x-8x-5 \\ -6x=\cancel{8x}-\cancel{8x}-5 \\ -6x=-5 \end{gathered}$

Step 4: Divide both sides by -6

$\begin{gathered} \frac{-6x}{-6}=\frac{-5}{-6} \\ x=\frac{5}{6} \end{gathered}$

Step 5: Get the value of 12x. Substitute x = 5/6 into the expression to have:

$\begin{gathered} 12x=12(\frac{5}{6}) \\ 12x=\cancel{12}^2(\frac{5}{\cancel{6}^1}) \\ 12x=2\times5 \\ 12x=10 \end{gathered}$

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