.760 rounded to the nearest tenth

Allyson loves to eat cheese sticks. A small order comes with 3 cheese sticks, and a large order comes with 6 cheese sticks. Last

lisabon 2012 [21]

Allyson loves to eat cheese sticks. A small order comes with 3 cheese sticks, and a large order comes with 6 cheese sticks....

Answer : 5

4 0

4 years ago

Read 2 more answers

Math: Please help me I don’t understand and I need to do corrections.

GREYUIT [131]

So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
${2}^{2} \times 3 \times 5 \\ and \\ {2}^{2} \times {3}^{2} \times 5 \times 7$
each have two twos. both have one 5, so we know our answer will look something like
${2}^{2} \times 5 \times other \: stuff$
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

one has one 3 and one has two, so we need two threes. now our equation is
${2}^{2} \times {3}^{2} \times 5 \times stuff$

what's the only number we have to deal with? 7...

how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes

4 0

3 years ago

What is the sum of -6 and 9

katrin2010 [14]

Positive 3, If You're starting at -6 and you add the first 6 it's at 0, now you have 3 more to add to make 9. And that gives you positive 3. or if you do 9 - 6 you can get your answer that way too.

7 0

3 years ago

Y <img src="https://tex.z-dn.net/?f=y%20%5Cleqslant%20%20-%20%20x%20-%201%20%5C%5C%20y%20%5Cgeqslant%202x%20%2B%204" id="TexF

Flura [38]

$y\leq-x-1\\\\y=-x-1\\for\ x=-1\to y=-(-1)-1=1-1=0\to(-1;\ 0)\\for\ x=0\to y=-0-1=-1\to(0;-1)$

$y\geq2x+4\\\\y=2x+4\\for\ x=-2\to y=2\cdot(-2)+4=-4+4=0\to(-2;\ 0)\\for\ x=0\to y=2\cdot0+4=0+4=4\to(0;\ 4)$

Answer in an attachment.

3 0

3 years ago

Based on information from a large insurance company, 67% of all damage liability claims are made by single people under the age

svetoff [14.1K]

Answer:

We conclude that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company.

Step-by-step explanation:

We are given that based on information from a large insurance company, 67% of all damage liability claims are made by single people under the age of 25.

A random sample of 52 claims showed that 43 were made by single people under the age of 25.

Let p = population proportion of claims made by single people

So, Null Hypothesis, $H_0$ : p $\leq$ 67% {means that the insurance claims of single people under the age of 25 is smaller than or equal to the national percent reported by the large insurance company}

Alternate Hypothesis, $H_A$ : p > 67% {means that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company}

The test statistics that will be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of claims made by single people under the age of 25 = $\frac{43}{52}$ = 0.83

n = sample of claims = 52

So, the test statistics = $\frac{0.83-0.67}{\sqrt{\frac{0.67(1-0.67)}{52} } }$

= 2.454

The value of z-test statistics is 2.454.

Since in the question, we are not given the level of significance so we assume it to be 5%. Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 2.454 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company.

6 0

4 years ago