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Reika [66]
3 years ago
9

Michael writes down 4 different factors of 60

Mathematics
2 answers:
Igoryamba3 years ago
7 0

Answer-

1. 1 + 2 + 3 + 20 = 26

2. 1 + 2 + 5 + 20 = 28

3. 1 + 2 + 6 + 12 = 21

4. 1 + 2 + 6 + 20 = 29

5. 1 + 2 + 10 + 12 = 25

6. 1 + 2 + 10 + 20 = 33

7. 1 + 3 + 5 + 12 = 21

8. 1 + 3 + 5 + 20 = 29

9. 1 + 3 + 6 + 12 = 22

10. 1 + 3 + 6 + 20 = 30

11. 1 + 3 + 10 + 12 = 26

12. 1 + 3 + 10 + 20 = 34

13. 1 + 5 + 6 + 10 = 22

14. 1 + 5 + 6 + 12 = 24

15. 1 + 5 + 6 + 20 = 32

16. 1 + 5 + 10 + 12 = 28

17. 1 + 6 + 10 + 12 = 29

18. 2 + 3 + 5 + 12 = 22

19. 2 + 3 + 5 + 20 = 30

20. 2 + 3 + 6 + 10 = 21

21. 2 + 3 + 6 + 12 = 23

22. 2 + 3 + 6 + 20 = 31

23. 2 + 3 + 10 + 12 = 27

24. 2 + 5 + 6 + 10 = 23

25. 2 + 5 + 6 + 12 = 25

26. 2 + 5 + 6 + 20 = 33

27. 2 + 5 + 10 + 12 = 29

28. 2 + 6 + 10 + 12 = 30

29. 3 + 5 + 6 + 10 = 24

30. 3 + 5 + 6 + 12 = 26

31. 3 + 5 + 6 + 20 = 34

32. 3 + 5 + 10 + 12 = 30

33. 3 + 6 + 10 + 12 = 31

34. 5 + 6 + 10 + 12 = 33

Rama09 [41]3 years ago
6 0

Answer:

Michael is smart

I am not. I hope Michael makes it to college

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so there is a 6/36 reduced to 1/6 probability of them matching

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4 years ago
Chelsea wants to rearrange her room. She makes a scale drawing of the room and cuts out
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Answer: B: 1 1/3 feet by 3 feet

Step-by-step explanation:

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4 years ago
A survey shows that college students spend on average about $20 per month on Yum Good Ramen. a. Assume that the survey was condu
lawyer [7]

Answer:

a) The 95% confidence interval would be given by (19.168;20.832)

b) The 95% confidence interval would be given by (19.182;20.416)

c) The 95% confidence interval would be given by (19.412;20.588)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

\sigma represent the population standard deviation

n represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

20-1.96\frac{6}{\sqrt{200}}=19.168    

20+1.96\frac{6}{\sqrt{200}}=20.832

So on this case the 95% confidence interval would be given by (19.168;20.832)

Part b

For this case we just need to change the value for the deviation

20-1.96\frac{3}{\sqrt{200}}=19.584    

20+1.96\frac{3}{\sqrt{200}}=20.416

So on this case the 95% confidence interval would be given by (19.182;20.416)

Part c

For this case we change again the deviation and the sample size.

20-1.96\frac{6}{\sqrt{400}}=19.412    

20+1.96\frac{6}{\sqrt{400}}=20.588

So on this case the 95% confidence interval would be given by (19.412;20.588)

7 0
3 years ago
Find the difference. 8x-(12x^2+5x)=
valentinak56 [21]

Answer:

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Step-by-step explanation:

8x-(12x^2+5x)

<em>difference</em>

<u>f ( x + h )   and   f ( x ) , and plug these values into the difference quotient formula</u>

− 24 x − 12 h +3

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Recursive definitions for subsets of binary strings.Give a recursive definition for the specified subset of the binary strings.
dmitriy555 [2]

Answer:

Step-by-step explanation:

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b2n+32n+3 = 2 (2n+2)22 b2n+12n+1

your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:

1. Either placing a 1 in available n places (because you can't place it at the end)

2. or by placing a zero in available n+1 places.

0 ϵ P

x ϵ P → 1x ϵ P , x1 ϵ P

x' ϵ P,x'' ϵ P → xx'x''ϵ P

3 0
3 years ago
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