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lana [24]
3 years ago
11

Find the inverse function of h(x)=2x-1/3

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0
To find inverse, you switch x and y, and solve for y
Original: y=2x-1/3
Now: 
x=2y-1/3
x+1/3=2y
(x+1/3)/2=y
y=\frac{x+ \frac{1}{3} }{2}
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The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

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First, we shall simplify the given expression.

Thus, we have,

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\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

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Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

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