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astra-53 [7]
3 years ago
14

How long will it takes to ski a distance of 25 miles at a constant speed of 5 miles per 30 minutes?​

Mathematics
2 answers:
Gala2k [10]3 years ago
7 0

Answer:

2 hours and 30 minutes

Step-by-step explanation:

25/5 = 5 Divide to find out how many fives are there in 25.

5 x 30 = 150 minutes (multiply 5 by 30 to find out how many minutes)

150/60 = 2.5 hours or in other words, 2 hours and 30 minutes ( Convert the minutes into hours by dividing by 60)

Marina86 [1]3 years ago
5 0
I think the answer is 150 minutes or 2 and a half hours
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three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are
goldenfox [79]
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12

the answer is
point (-5,12)

see the attached figure

6 0
3 years ago
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Tems11 [23]
Shape B because a pentagon has 5 sides

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1st Step: 3 - 4x - 7 = -24<br> 2nd Step: 3- 7 - 4x = -24<br> What property justifies the 2nd step
gizmo_the_mogwai [7]

Answer:

the subtraction

Step-by-step explanation:

3 0
3 years ago
Please help asap find f -1
ExtremeBDS [4]
I.
Given a function f with domain D and range R, and the inverse function 
f ^{-1},

then the domain of f ^{-1} is the range of f, and the range of f ^{-1} is the domain of f.

II. We are given the function f(x)= \sqrt{x-5},

the domain of f, is the set of all x for which \sqrt{x-5} makes sense, so x is any x for which x-5\geq0, that is x≥5.

the range is the set of all values that f can take. Since f is a radical function, it never produces negative values, in fact in can produce any value ≥0

Thus the Domain of f is [5, ∞) and the Range is [0, ∞)
then , the Domain of f ^{-1} is [0, ∞) and the Range of f ^{-1} is [5, ∞) 

III.
Consider f(x)= \sqrt{x-5}

to find the inverse function f^{-1}, 

1. write f(x) as y:

y= \sqrt{x-5}

2. write x in terms of y:

y= \sqrt{x-5}

take the square of both sides

y^{2} =x-5

add 5 to both sides

y^{2} +5=x

x=y^{2} +5

3. substitute y with x, and x with f^{-1}(x):

f^{-1}(x)=x^{2} +5


These steps can be applied any time we want to find the inverse function.

IV. Answer: 

f^{-1}(x)=x^{2} +5, x≥0

y≥0, where y are all the values that f^{-1} can take

Remark: the closest choice is B

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