Well, let's first write these as points.
( 2 , 50 )
( 4 , 100 )
We can see that when "x" is reduced by 2, "y" is reduced by 50. This means that if we reduce "x" by 1, "y" will be reduced by 25. Thus, we can say that if "x" is 1, "y" will be 25.
( 1 , 25 )
What we know that 25 * 1 = 25, and that 2 * 25 = 50. We can see that multiplying "x" by 25 will give us our "y". We can now write this as an equation.
y = 25x
Answer:
x = 5
Step-by-step explanation:
=(-5-√-75)/2=(-5-5i√ 3 )/2= -2.5000-4.3301i
x =(-5+√-75)/2=(-5+5i√ 3 )/2= -2.5000+4.3301i
x = 5
source tiger-algebra.com
Answer:
11 is the median of the entire data set
6 is the median of the lower half and 16 is the median of the upper half data scores...
Subtract 16 from 6 gives 10 so the answer is C) 10
Answer:
Option E is correct.
- Treatments: how the peppermint oil is dispersed
- Experimental unit: mice
- Response variable: number of mice in the dwellings
Step-by-step explanation:
The treatments in this type of statistical experiment refers to the part of the experiment that is tweaked, controlled or varied in the cases being studied. In this experiment, the method of essential oil dispersal is what is varied in the two experimental cases of this study.
Experimental Unit refers to the subject matters, who are participants in the experiment. They are the ones that the effect of the treatments is tested upon.
For this study, the experimental units are the mice subjected to either of the two methods of peppermint oil dispersal.
The response variable is how the experimental units (participants) respond to the treatments (experimental tweaks). Or how the tweaks manifest observable results in the participants of the study. For this study, the effect of the tweaks in the mice is shown in the number of mice that remain in each dwelling (where the two methods of peppermint oil dispersal have been implemented). Hence, the response variable is the number of mice in each dwelling.
Hope this Helps!!!
Answer:
Step-by-step explanation:
cylinder's height=3×(diameter of sphere)=3×6=18 cm
radius of cylinder=3 cm
volume of cylinder=π r²h=π(3)²×18=162 π cm³
volume of sphere=4/3 π(3)³=36 π cm³
reqd. empty space=162 π-3×36π=54 πcm³