Question

7. Write the equation of a line which passes through the points (-3,5) and (6,23)

Answer 1

Answer:

answer to the equation is

$y = 2x + 11$

Step-by-step explanation:

$y = mx + b$

first find the slope of the line using the two points

$slope \: m = \frac{y2 - y1}{x2 - x1} = \frac{23 - 5}{6 - ( - 3)} \\ = \frac{18}{9} \\ slope \: m = 2$

substitute 2 for m and use one of the points for x and y and solve for b

$5 = 2( - 3) + b \\ 5 = - 6 + b \\ 5 + 6 = b \\ b = 11$

Now that you found b, the y-intercept, you can substitute that into the equation for your line

$y = 2x + 11$