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Mathematics

2 answers:

leva [86]3 years ago

5 0

Answer:

c. 135 hr

Step-by-step explanation:

The following method of converting units is called "dimensional analysis."

Write every conversion factor as a fraction. Each conversion factor fraction equals 1, so it changes units but not the value. In the end, all the undesired units cancel out leaving the desired units. Multiply the given amount by the necessary conversion factors until you arrive at the desired units.

$3~extra~bagal \times \dfrac{10~sobrang~bagal}{1~extra~bagal} \times \dfrac{3~bagal}{1~sobrang~bagal} \times \dfrac{90~min}{1~bagal} \times \dfrac{1~hr}{60~min} =$

$= 135~hr}$

vlada-n [284]3 years ago

3 0

Answer:

Step-by-step explanation:

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An instructor gives her class the choice to do 7 questions out of the 10 on an exam.

Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

$10C7=\frac{10!}{7!(10-7)!}=120$

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

$(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50$

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

$(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50$

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

$(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10$