Answer:
RTMC pro, HTML server-sent and Java Software Development Kit
Explanation:
<u>RTMC pro</u>: The setup of RTMC pro is done automatically and there is provision of several elements to upload and store data on the server using screens. Screens are usually saved as files and then integrated to an internal or external server.
<u>HTML server-sent</u> : This is a way for webpages to communicate with the webserver. In this method, for ever HTML page there is an associated script present on the server side that will continuously provide realtime data update. This scrip will have to be configured with the data you want to update.
<u>Java Software Development Kit</u> : JAVA SDK is used to build software/applications on Java. This permits programmers to develop applications or applets to perform data updating on the servers. The developped applets can be used with internal servers as well as third party servers.
Answer:
Explanation:
Farmers are always both directly and indirectly connected to each other
Their network is mostly strong
Networks become weak only on the edges (ends) of the river but doesn't completely dimnish
With the available network length, the center of river bank forms the strongest network of all and becomes a key player in defining the balance property of overall network
The network is very well structurally balanced and we can see that through the below image
20 miles 10 20 30 40 50
See attachment file for diagram
Considering the total length of river as 50miles and and the center of the whole length will be at 25th mile. From that point, if we consider a farmer will be be having friends for a length of 20miles both along upstream and downstream.
By this he'll be in friend with people who are around 80% of the total population. As me move from this point the integrity increases and this results in a highly balanced structural network.
I believe it’s problem solving.
def dx(fn, x, delta=0.001):
return (fn(x+delta) - fn(x))/delta
def solve(fn, value, x=0.5, maxtries=1000, maxerr=0.00001):
for tries in xrange(maxtries):
err = fn(x) - value
if abs(err) < maxerr:
return x
slope = dx(fn, x)
x -= err/slope
raise ValueError('no solution found')
I would say A because it was talking about something in the present but what they were talking about was in past. so I would think A
