<span>Which of the following inequalities is correct?
-9 ≥ -7 is wrong as 9>7 but -9 < -7
-10 > |-10| is wrong as </span>|-10|= 10<span>
6 ≤ |-6| is right cause </span>|-6| =6 and we have 6=6 or <span>6 ≤ |-6| is also right</span><span>
0 < -13 is totally wrong
Have fun</span>
The answer is -2a^4+4a^2b^2+5b^2a%
-7 ÷ 2 1/2
Okay, so first, put the -7 over one and make 2 1/2 an improper fraction. so now:
-7/1 ÷ 5/2
Then, take the reciprocal of 5/2 and multiply it by -7/1
-7/1 × 5/2
Which would be -35/2
N<span><span><span>3</span><span></span></span>+4<span>n<span><span>2</span><span></span></span></span>+8n−16
hope helped
</span>
Ok so to find the ratio just do 12/16 = 3/4. that's your common ratio.
The formula for sum of infinite :
a / (1 - r)
a is the first term and r is the ratio
which is
16 / (1 - (3/4))
which is
16 / (1/4)
16 * 4
which is 64
