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Lady bird [3.3K]
3 years ago
11

Factor the expression 8q^6r^3+27s^6t^3

Mathematics
2 answers:
OverLord2011 [107]3 years ago
7 0

Find the coordinates of p so that p partitions AB in the ratio 1 to 3 with a(-5,4) and(7,-4) Step-by-step explanation:


Korolek [52]3 years ago
3 0

8q^6r^3+27s^6t^3

this is the sum of cubes:  a^ 3 + b^ 3 = (a + b) (a^ 2 − a b + b^ 2 )

where a = 2q^2r and b=3s^2t

(2 q^2 r + 3 s^2 t) (4 q^4 r^2 - 6 q^2 r s^2 t + 9 s^4 t^2)

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Find the slope of the line passing through the points (-7,9) and (2,9).<br> slope=
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Answer:  The slope is 0

Step-by-step explanation:

The slope is the difference between the y coordinates divided by the difference between the x coordinates.

Y:  9 - 9 = 0

x: -7-2 =   -9

0/-9= 0  

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3 years ago
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3 years ago
Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En
ArbitrLikvidat [17]

Answer:

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, c) x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right), y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right).

Step-by-step explanation:

The equation of the circle is:

x^{2} + (y-1)^{2} = 16

After some algebraic and trigonometric handling:

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t

Where:

\frac{x}{4} = \cos t

\frac{y-1}{4} = \sin t

Finally,

x = 4\cdot \cos t

y = 1 + 4\cdot \sin t

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

c) x = 4\cdot \cos t'', y = 1 + 4\cdot \sin t''

Where:

4\cdot \cos t' = 0

1 + 4\cdot \sin t' = 5

The solution is t' = \frac{\pi}{2}

The parametric equations are:

x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right)

y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)

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3 years ago
5/6+5/6 show your work
Umnica [9.8K]
10/6 = 1 2/3 This is because 5 + 5 =10/6 Divide 19 by six. This gives you 1 2/3
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