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3 years ago

Factor the expression 8q^6r^3+27s^6t^3

Mathematics

2 answers:

OverLord2011 [107]3 years ago

7 0

Find the coordinates of p so that p partitions AB in the ratio 1 to 3 with a(-5,4) and(7,-4) Step-by-step explanation:

Korolek [52]3 years ago

3 0

8q^6r^3+27s^6t^3

this is the sum of cubes: a^ 3 + b^ 3 = (a + b) (a^ 2 − a b + b^ 2 )

where a = 2q^2r and b=3s^2t

(2 q^2 r + 3 s^2 t) (4 q^4 r^2 - 6 q^2 r s^2 t + 9 s^4 t^2)

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How do you find the limit?

coldgirl [10]

Answer:

2/5

Step-by-step explanation:

Hi! Whenever you find a limit, you first directly substitute x = 5 in.

$\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{5^2-6(5)+5}{5^2-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{25-30+5}{25-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{0}{0}}$

Hm, looks like we got 0/0 after directly substitution. 0/0 is one of indeterminate form so we have to use another method to evaluate the limit since direct substitution does not work.

For a polynomial or fractional function, to evaluate a limit with another method if direct substitution does not work, you can do by using factorization method. Simply factor the expression of both denominator and numerator then cancel the same expression.

From x²-6x+5, you can factor as (x-5)(x-1) because -5-1 = -6 which is middle term and (-5)(-1) = 5 which is the last term.

From x²-25, you can factor as (x+5)(x-5) via differences of two squares.

After factoring the expressions, we get a new Limit.

$\displaystyle \large{ \lim_{x\to 5}\frac{(x-5)(x-1)}{(x-5)(x+5)}}$

We can cancel x-5.

$\displaystyle \large{ \lim_{x\to 5}\frac{x-1}{x+5}}$

Then directly substitute x = 5 in.

$\displaystyle \large{ \lim_{x\to 5}\frac{5-1}{5+5}}\\

\displaystyle \large{ \lim_{x\to 5}\frac{4}{10}}\\

\displaystyle \large{ \lim_{x\to 5}\frac{2}{5}=\frac{2}{5}}$

Therefore, the limit value is 2/5.

L’Hopital Method

I wouldn’t recommend using this method since it’s too easy but only if you know the differentiation. You can use this method with a limit that’s evaluated to indeterminate form. Most people use this method when the limit method is too long or hard such as Trigonometric limits or Transcendental function limits.

The method is basically to differentiate both denominator and numerator, do not confuse this with quotient rules.

So from the given function:

$\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}$

Differentiate numerator and denominator, apply power rules.

Differential (Power Rules)

$\displaystyle \large{y = ax^n \longrightarrow y\prime= nax^{n-1}$

Differentiation (Property of Addition/Subtraction)

$\displaystyle \large{y = f(x)+g(x) \longrightarrow y\prime = f\prime (x) + g\prime (x)}$

Hence from the expressions,

$\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2-6x+5)}{\frac{d}{dx}(x^2-25)}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2)-\frac{d}{dx}(6x)+\frac{d}{dx}(5)}{\frac{d}{dx}(x^2)-\frac{d}{dx}(25)}}$

Differential (Constant)

$\displaystyle \large{y = c \longrightarrow y\prime = 0 \ \ \ \ \sf{(c\ \ is \ \ a \ \ constant.)}}$

Therefore,

$\displaystyle \large{ \lim_{x \to 5} \frac{2x-6}{2x}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{2(x-3)}{2x}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{x-3}{x}}$

Now we can substitute x = 5 in.

$\displaystyle \large{ \lim_{x \to 5} \frac{5-3}{5}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{2}{5}}=\frac{2}{5}$

Thus, the limit value is 2/5 same as the first method.

Notes:

If you still get an indeterminate form 0/0 as example after using l’hopital rules, you have to differentiate until you don’t get indeterminate form.

8 0

2 years ago

The temperature one afternoon at 3 PM

prohojiy [21]

Answer:

Your answer is 49 degrees

Step-by-step explanation:

66 - 17 = 49

7 0

3 years ago

Use the drop-down menus to complete the statements. The ordered pair given in the first row in the table can be written using fu

kvv77 [185]

f(x) is read is function f of x.

Where x is the input variable and function f(x) gives output value of function for x input value.

For the given function, we have f(3).

If we compare f(3) by f(x), the x represented by input value 3.

Therefore, x value is 3 there.

And we also have f(x) =-5.

Because function value is -5. So we can read it as, "for x input value of the the function gives output value -5."

For the asked value of x is just x=3.

4 0

3 years ago

Read 2 more answers

VERY VERY URGENT!!!!!!!

Arte-miy333 [17]

The answer is 7/25, because cos is opposite/hypothenuse.

3 0

3 years ago

3. There are 25 students in the debate

Savatey [412]

Answer:

60%

Step-by-step explanation:

To make a percent, it needs to be out of 100. So, the fraction would be 15/25. To make it 100, multiply each by 4 to get 100 since 25 times 4 equals 100. 15 times 4 is 60, so its 60 percent.

8 0

2 years ago

Read 2 more answers