Answer:
Probability that the proportion of airborne viruses in a sample of 529 viruses would be greater than 8% is 0.9545.
Step-by-step explanation:
For the given population the distribution of air-borne viruses is given as 6%. Now for this the value of Z score is given as

Here
is the sample measure which is 8% or 0.08- p is the population measure which is 6% or 0.06
- n is the number of samples which is 529
So the Z score is given as

For this the score, the value of probability is calculated from the table as below:

Here value of p(Z<-1.6955) is given as 0.0455

Answer:
6.72<x<10.08
Step-by-step explanation:
multiply 1.12 and 6 for the low end
multiply 1.12 and 9 for the high end
Answer:
76
Step-by-step explanation:
Survey response
Those who liked the proposed plan=380 persons
Those who didn't like the proposed plan=120 persons
We assume that the these are the only people who participated, with those who never took sides being zero
Total number of people surveyed=380 persons+120 persons=500 persons
Percentage of those who liked =
Therefore, the percentage that liked the plan is 76%
Answer:
-4
Step-by-step explanation: