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Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
Answer:
Step-by-step explanation:
-0.5(3x + 5) and -1.5x + 2.5
-0.5(3x + 5)...distribute the -0.5 thru the parenthesis
-1.5x - 2.5
no, these are not equivalent.... one is -1.5x + 2.5 and the other is -1.5x - 2.5....not the same
5
the factors of 20 are 1, 2, 4, 5, 10, 20
the factors of 15 are 1, 3, 5, 15
the common factor of 20 and 15 is 5
