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Kay [80]
3 years ago
15

Find the x and y intercepts of this function. h(x) = 2x^2 - 3x - 2 Please help me

Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0

Answer:

The x-intercepts: (-0.5, 0) and (2, 0)

The y-intercept: (0, -2)

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Which expression is equivalent to 2x² + 7x + 4?
Elina [12.6K]

Answer:

none of these

Step-by-step explanation:

2x² + 7x + 4

Factor

We cannot factor this since 2*4 +1 = 9 and we want 7

and 2*2 +2 = 6 and we want 7

and 2*1 +4 = 6 and we want 7

7 0
3 years ago
When solving the equation 3(2x+6) +8=15,
Anika [276]

Answer:

see below

Step-by-step explanation:

3(2x+6) +8=15

Subtract 8 from each side using the subtraction property of equality

3(2x+6) +8-8=15-8

3(2x+6) =7

3 0
2 years ago
Read 2 more answers
Bill manages a restaurant. He schedules most of his employees to work on saturdays and fridays at night. If 24 of the 40 employe
Julli [10]

Answer:

40%

Step-by-step explanation:

40-24=16

16/40 ×100 =40%

8 0
3 years ago
A smart phone manufacturer uses 10 ounces of gold circuitry to make 5,200 smart phones. If they made 7,800 smart phones last mon
padilas [110]

Answer:

$19,500

Step-by-step explanation:

In this question, the first thing we do

Is to calculate the amount of gold that was used in making 7,800 smartphones. We proceed as follows:

Firstly, 10 ounces made 5,200 smartphones, then x ounces will make 7,800 smartphones

Thus 10 * 7,800 = 5,200 * x

x = 78,000/5200 = 15 ounces

This means that 7,800 smartphones were made using 15 ounces of gold

Now, we know that the value of an ounce is $1,300. Thus, the value of 15 ounces would be 15 * 1,300 = $19,500

8 0
3 years ago
What is the overtime rate for lifeguard who regularly earns $8.75 per hour?
TEA [102]
The overtime rate is an added percentage to the regular rate. By how much percentage, this would depend on the place you're working. If your work in USA, under US federal labor and tax law, the rate would be 150%. Thus, the overtime rate would then be:

Overtime rate = $8.75/hour * 1.50 = $13.125/hour
3 0
3 years ago
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