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3 years ago

How do you write 50.3% as a decimal

Mathematics

1 answer:

shutvik [7]3 years ago

8 0

.503 is written as a decimal.
You move the dot left 2 times

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If your car can travel 20 miles on 1 gallon of fuel how many litres were used to travel 130 miles? Step by step

Bezzdna [24]

Answer:2600 Gallons

Step-by-step explanation: You first have to take 130 and times it by 20 then times it by 1. make sure you add labels

3 0

3 years ago

A triangular prism container is full of water of 428 cubic cm. The water is 10 cm deep, what is the base area of the container?

Hatshy [7]

<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>

Solution:

The volume of triangular prism is given as:

$v = base\ area \times height$

Given that,

A triangular prism container is full of water of 428 cubic cm

The water is 10 cm deep

Therefore,

v = 428 cubic cm

h = 10 cm

Substituting the values we get,

$428 = base\ area \times 10\\\\base\ area = \frac{428}{10}\\\\base\ area = 42.8\ cm^2$

Thus the base area of triangular prism container is 42.8 cubic centimeter

3 0

4 years ago

Please someone factorise x^2 + 8x + 16

lukranit [14]

Answer:

i tihnk it is = − 4 im sorry if it is wrong

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the measure of _RVE?

marysya [2.9K]

Answer:

D. 45

Step-by-step explanation:

All angles have to = 180°

60 + 75 + <RVE = 180°

135 + RVE = 180°

180 - 135 = 45° RVE

RVE = 45°

Another way to check your answer:

Add all of the angles, and it should equal 180°

60 + 75 + 45 = 180°

Correct!

6 0

3 years ago

Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as a sum, difference,

Leya [2.2K]

Answer: $\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]$

Step-by-step explanation:

Properties of logarithm :

$\log (ab)= \log a+\log b$
$\log(\dfrac{a}{b})=\log a-\log b$
$\log a^n= n\log a$

The given expression in terms of Natural log : $\ln (x^2 - 1)^{\frac{1}{3}}$

This will become $\dfrac{1}{3}\ln (x^2 - 1)$ [ By using Property (3)]

$=\dfrac{1}{3}\ln (x^2-1^2)$

$=\dfrac{1}{3}\ln ((x+1)(x-1))$ [ $\because a^2-b^2=(a+b)(a-b)$ ]

$=\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]$ [ By using Property (1)]

Hence, the simplified expression becomes $\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]$ .

5 0

3 years ago