Ask question

Ask question

All categories

3 years ago

9

Find the volume of the cylinder. What is the exact volume in terms of π? (diameter= 16m) Options a.) 1000pi cubic m b.) 1024pi c

ubic m c.) 4096pi cubic m d.) 4000 cubic m PLEASE HURRY I WILL GIVE BRAINLIEST

1 answer:

Kazeer [188]3 years ago

6 0

The volume for any cylinder, right or oblique, would be base x height. Even though an oblique cylinder looks quite different from a right cylinder, their volumes would be equal (given that their radius and height are equal). Think about it, the area of a parallelogram would equal the area of the rectangle if their heights and bases were the same, so that would apply for this also.

V= Bh
The base would stand for that top and bottom of the cylinder, or the circles. The volume for circle is pi x radius squared.
V = $\pi r^{2}$ h
V = $\pi$ 256 x 16
V = $\pi$ 4096 $m^{3}$

You might be interested in

A Ferris wheel has a radius of 10 m, and the bottom of the wheel passes 1 m above the ground. If the Ferris wheel makes one comp

Volgvan

Answer: $1+10(1-\cos (\frac{\pi t}{9}))$

Step-by-step explanation:

Given

radius of wheel $r=10 m$

Time period of Wheel $T=18 s$

and $T\cdot \omega =2\pi$ , where $\omega =angular velocity of wheel$

$\omega =\frac{2\pi }{18}$

Let at any angle $\theta$ with vertical position of a point is given by

$x=r\sin \theta$

$y=y_0+r(1-\cos \theta )$

and $\theta =\omega \times t$

for velocity differentiate x and y to get

$v_x=r\cos \theta =r\cos (\omega t)$

$v_y=0+r(\sin \theta )=r\sin (\omeag t)$

Height at any time t is given by

$h=1+10(1-\cos \theta )=1+10(1-\cos (\frac{\pi t}{9}))$

7 0

3 years ago

Please Help........................................................

larisa [96]

$2(n-5)\geq2n+10\\2n-10\geq2n+10\\-10\geq 10\\n\in\emptyset$

8 0

3 years ago

A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the

denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

Therefore, area of the base = x² ft²

Cost of the material to prepare the base = $0.35 per square feet

Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

$y=\frac{20}{x^{3} }$ -----(1)

Cost of the material for the sides = $0.10 per square feet

Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

= $0.40xy

Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost $C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}$

$C=0.35x^{2}+\frac{8}{x}+0.15x^{2}$

$C=0.5x^{2}+\frac{8}{x}$

Now we take the derivative of C with respect to x and equate it to zero,

$C'=0.5(2x)-\frac{8}{x^{2}}$ = 0

$x-\frac{8}{x^{2}}=0$

$x=\frac{8}{x^{2} }$

$x^{3}=8$

x = 2 ft.

From equation (1),

$(2)^{2}y=20$

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

8 0

3 years ago

Find the missing side. Round to the nearest tenth.

puteri [66]

Answer:

29.9

Step-by-step explanation:

29.9 rounded to the nearest 10 is 30

4 0

2 years ago

Find the largest positive integer that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively.

marin [14]

Required number is 17.

<h3>Justification:</h3>

<u>We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively</u>.

Hence, we need to find the HCF of 3 numbers (398-7), (436-11) and (542-15).

Hence,

398 - 7 = 391
436 - 11 = 425
542 - 15 = 527

Now, you can find the HCF(391, 425, 527) = 17

<u>Hence, the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17</u>.

8 0

2 years ago

Read 2 more answers