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Ksenya-84 [330]
2 years ago
7

4 1/2 : 3 1/4 change into simplest form of ratio help fast please​

Mathematics
2 answers:
lianna [129]2 years ago
8 0

Answer:

4 1/2=9/2 3 1/4=13/4

Step-by-step explanation:

Hope I helped!

Have a great day!

erastovalidia [21]2 years ago
4 0
4 1/2 = 9/2 = 18/4
3 1/4 = 13/4

Lose the denominators and the ratio is 18:13
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Find the remainder when f(x) = x^3 + 14x^2 − 7x − 10 is divided by x − 3.
Elanso [62]

Answer:

122

Step-by-step explanation:

(3)³ + 14(3²) - 7(3) - 10

122

Used remainder theorem

6 0
3 years ago
I need help with these 2 questions!! please 20 points!!!
bezimeni [28]

9514 1404 393

Answer:

  1. 45 cm²
  2. 38 cm²

Step-by-step explanation:

The conventional way to work these problems is to make use of the formulas for areas of a triangle, rectangle, and semicircle. If you've used these formulas for a while, you recognize that they give you certain relationships that may make these problems easy to do mentally.

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1. The area of a triangle is half the product of height and width, so is equivalent to the area of a rectangle either half as high, or half as wide. We note that the width of the sail is 5 cm, so half that is 2.5 cm--exactly the same as the height of the boat's hull. That means we can add the height of the sail to the length of the boat, and the total area can be considered to be the same as that of a rectangle that is

  2.5 cm high × (12 cm + 6 cm) long = (2.5)(18) cm² = 45 cm²

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2. The usual formula for the area of a circle is ...

  A = πr²

When expressed in terms of diameter, this becomes ...

  A = π(d/2)² = (π/4)d²

Then the area of a semicircle is half that, or (π/8)d². This is equivalent to the area of a rectangle that is "d" wide and "π/8·d" high. That is, the approximate area of the semicircle is that of a rectangle 4 cm high by (π/8·4 cm) = π/2 cm wide. In other words, the semicircle effectively adds π/2 cm to the left end of the 6 cm central rectangle of the figure.

As discussed above, the area of a triangle is equivalent to the area of a rectangle half as high. In this figure, the triangle is 10-6 = 4 cm wide, so can be considered to contribute 4/2 = 2 cm to the right end of the 6 cm central rectangle.

If we consider π ≈ 3, then the approximate area of the figure is ...

  (4 cm)(3/2 cm + 6 cm + 2 cm) = (4)(9.5) cm² = 38 cm²

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The exact value is 4(8+π/2) = 32+2π ≈ 38.283 cm².

7 0
2 years ago
-5 x + y = - 21 and y = x - 1 solve the system of equation
Kitty [74]

Answer:

Step-by-step explanation:

-5x + (x -1) = -21

-4x = -20

x = 5

3 0
2 years ago
Rewrite the equation in standard form y = - 3/4 x - 6
notka56 [123]

Answer:

Step-by-step explanation:

y =\dfrac{-3}{4}x -6

Multiply the entire equation by 4,

4*y=\dfrac{-3}{4}x*4 - 6*4\\

4y = -3x - 24

Add 3x to both sides

3x + 4y = -24

Add 24 to both sides

3x + 4y + 24 = 0

6 0
2 years ago
An 11-m tall building casts a shadow. The distance from the top of the building to the tip of the shadow is 14 m. Find the lengt
Arte-miy333 [17]

Answer:

8.66 m

Step-by-step explanation:

Given that,

The distance from the top of the building to the tip of the shadow is 14 m

The height of the building is 11 m.

We need to find the length of the shadow. we can see that the length of the shadow forms the base of the triangle.

The distance from the top of the building to the tip of the shadow form hypotensue and height of the building forms perpendicular. So, we can use Pythagoras theorem to find the base.

So,

H^2=b^2+h^2\\\\b^2=H^2-h^2\\\\b=\sqrt{14^{2}-11^{2}}\\\\b=8.66\ m

So, the length of the shadow is 8.66 m.

7 0
3 years ago
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