Add: 5 + 3 = 8
Exponentiation: the result of step No. 1 ^ 2 = 8 ^ 2 = 64
Add: 32 + 2 = 34
Subtract: the result of step No. 2 - the result of step No. 3 = 64 - 34 = 30
Multiple: 5 * the result of step No. 4 = 5 * 30 = 150
Add: 8 + the result of step No. 5 = 8 + 150 = 158
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Each are divisible by 11 so the ratio equivalent would be 7:9
Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
Step-by-step explanation:
it 100 more than the 4 in 37,426
Answer:
15
Step-by-step explanation:
100 laps
100 divided by 20 Is 5
3 x 5 is 15
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