3 years ago

How do you solve the function y = 2.5^x for y=20

1 answer:

6 0

$y=2.5^x;\ y=20\\\\2.5^x=20\\\\log_{2.5}2.5^x=log_{2.5}20\\\\x=log_{2.5}20\\\\x=log_{2.5}(2.5\cdot8)\\\\x=log_{2.5}2.5}+log_{2.5}8\\\\x=1+log_{2.5}8$

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