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AVprozaik [17]
3 years ago
12

Please helpppppppppppppppppppp

Physics
1 answer:
givi [52]3 years ago
7 0

Answer:

Explanation:

what do you really need help with

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A force of 6.0 N acts on a 3.0 kg object at rest for 10 seconds.
MAVERICK [17]

The beginning momentum of the object is zero

Explanation:

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is its velocity

For the object in this problem, we have:

m = 3.0 kg is its mass

v = 0, because it is initially at rest, so its initial velocity is zero

Therefore, the initial momentum of the object is

p=(3.0)(0)=0

Learn more about momentum:

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3 years ago
As the skydiver's ______increases, so does the magnitude of the force due to friction.
Basile [38]

Answer:

speed?

Explanation:

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7 0
3 years ago
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What would you like to see if you were visiting Mars?
Olegator [25]

Answer:

I would like aliens if they exist

Explanation:

5 0
4 years ago
It is weigh-in time for the local under 85 kg rugby team. The bathroom scale used to assess eligibilty can be described by Hooke
Varvara68 [4.7K]
<span>k = 1.7 x 10^5 kg/s^2 Player mass = 69 kg Hooke's law states F = kX where F = Force k = spring constant X = deflection So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration. F = kX F/X = k 115 kg* 9.8 m/s^2 / 0.65 cm = 115 kg* 9.8 m/s^2 / 0.0065 m = 1127 kg*m/s^2 / 0.0065 m = 173384.6154 kg/s^2 Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2 Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So X/0.39 cm = 115 kg/0.65 cm X = 44.85 kg/0.65 X = 69 kg The player masses 69 kg.</span>
4 0
3 years ago
Read 2 more answers
You are explaining to your friends why astronauts feel weightless while orbiting in the space shuttle. They ask you to prove thi
meriva

Answer:

Explanation:

Force of gravity = GMm/r^2 = ma

a being the acceleration due to gravity at some distance r from the center of the Earth.  I'll use 6400 km for the radius of the Earth so r = 6734 km or 6734000 meters

a = GM/r^2

plugging in G = 6.67 x 10^-11

M is the mass of the Earth = 6 x 10^24

and r is from above

a = 8.825 m/s^2  = 0.9g

so 90% the acceleration of gravity on the surface.

5 0
3 years ago
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