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3 years ago

Plucking on a tight metal wire causes it to vibrate. What type of energy would that produce?

Physics

1 answer:

ExtremeBDS [4]3 years ago

4 0

Question one :sound Energy
Question two :light and thermal energy
I hope this helps you
A little bit I can do

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In a circuit of two lamps in parallel there is 5 v across one lamp. what is the voltage across the other lamp? answer in units o

natima [27]

The voltage across the other lamp is also 5 V.
In fact, when two resistances are connected in parallel, they are connected to the same points of the circuit. This also means that the potential difference across the two sides of the resistors is the same, therefore the voltage across the two lamps connected in parallel is 5 V for both.

3 0

3 years ago

The brakes on your automobile are capable of creating a deceleration of 4.6 m/s^2. If you are going 114 km/h and suddenly see a

drek231 [11]

Answer:

The minimum time to get the car under max. speed limit of 79 km/h is 2.11 seconds.

Explanation:

$a=\frac{V_f-V_0}{t}$

isolating "t" from this equation:

$t=\frac{V_f-V_0}{a}$

Where:

a= $-4.6m/s^2$ (negative because is decelerating)

$V_f= 79 km/h$

$V_0= 114 km/h$

First we must convert velocity from km/h to m/s to be consistent with units.

$79\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{79*1000}{3600}=21.94 m/s$

$114\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{114*1000}{3600}=31.67 m/s$

So;

$t=\frac{V_f-V_0}{a}=\frac{21.94 m/s-31.66m/s}{-4.6 m/s^2}=2.11 s$

7 0

3 years ago

If, instead, the ball is revolved so that its speed is 3.7 m/s, what angle does the cord make with the vertical?

Delicious77 [7]

Complete Question:

A 0.50-kg ball that is tied to the end of a 1.5-m light cord is revolved in a horizontal plane, with the cord making a 30° angle with the vertical.

(a) Determine the ball’s speed. (b) If, instead, the ball is revolved so that its

speed is 3.7 m/s, what angle does the cord make with the vertical?

(Check attached image for the diagram.)

Answer:

(a) The ball’s speed, v = 2.06 m/s

(b) The angle the cord makes with the vertical is 50.40⁰

Explanation:

If the ball is revolved in a horizontal plane, it will form a circular trajectory,

the radius of the circle, R = Lsinθ

where;

L is length of the string

The force acting on the ball is given as;

F = mgtanθ

This above is also equal to centripetal force;

$mgTan \theta = \frac{mv^2}{R} \\\\Recall, R = Lsin \theta\\\\mgTan \theta = \frac{mv^2}{Lsin \theta}\\\\v^2 = glTan \theta sin \theta\\\\v = \sqrt{glTan \theta sin \theta} \\\\v = \sqrt{(9.8)(1.5)(Tan30)(sin30)} \\\\v = 2.06 \ m/s$

(b) when the speed is 3.7 m/s

$v = \sqrt{glTan \theta sin \theta} \ \ \ ;square \ both \ sides\\\\v^2 = glTan \theta sin \theta\\\\v^2 = gl(\frac{sin \theta}{cos \theta}) sin \theta\\\\v^2 = \frac{gl*sin^2 \theta}{cos \theta} \\\\v^2 = \frac{gl*(1- cos^2 \theta)}{cos \theta}\\\\gl*(1- cos^2 \theta) = v^2cos \theta\\\\(9.8*1.5)(1- cos^2 \theta) = (3.7^2)cos \theta\\\\14.7 - 14.7cos^2 \theta = 13.69cos \theta\\\\14.7cos^2 \theta + 13.69cos \theta - 14.7 = 0 \ \ \ ; this \ is \ quadratic \ equation\\\\$