Answer:

Step-by-step explanation:
We know that:
In a deck of 52 cards there are 4 aces.
Therefore the probability of obtaining an ace is:
P (x) = 4/52
The probability of not getting an ace is:
P ('x) = 1-4 / 52
P ('x) = 48/52
In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.
For a discrete random variable V, the expected value is defined as:

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.
We have the following equation for the expected value:

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52
Therefore, expected value for V, the number of points obtained in the game is:

So:

4x-1=18
4x=18+1
4x=19
x=19/4
Answer:
There is a strong but negative correlation. The - cuases a doawnward line but .89 is close to 1
Step-by-step explanation:
Step-by-step explanation:
We will prove by contradiction. Assume that
is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that
. Then, for some integer
,

Therefore

Here we will use the formula for the sum of odd powers, which states that, for
and an odd positive number
,

Applying this formula in 1) we obtain that
.
Then, as
we have that
is not a prime number, which is a contradiction.
In conclusion, if
is an odd prime, then n must be a power of 2.
The answer to your question is -20 i hope this helps!