Question

3

Answer 1

• To find the maximum value of the function, we need to know the vertex of the parabola

• $\large \boldsymbol {} \displaystyle ax^2+bx+c=0 \\\\ \boldsymbol{x_v=-\frac{b}{2a} } \\\\\\ \boldsymbol {y_v=ax_v+bx_v+c}$  

• Where    $\large \boldsymbol {x_v \ \ ; \ \ y_v}$ - are the coordinates of the vertex of the parabola

• $\large \boldsymbol \displaystyle {} f(x)=-(x+2)^2+8 = -1\cdot x^2-4x+4 \\\\\\ \displaystyle x_v=-\frac{-4}{-2} =-2 \\\\\\y_v=-(-2+2)^2+8 =8$  

• The graph in the attached file

Answer 2

Answer:

= 14

Step-by-step explanation:

x = x + 22 - 8

x = x + 14

x = x + 14

x - x = x + 14 - x

simplfy

all of it

=14