3 years ago

I need help if 12 counters are 3/4of a set then what is the whole set

Mathematics

2 answers:

Luba_88 [7]3 years ago

7 0

The whole answer is 16 counters
Hope this helps

jeyben [28]3 years ago

5 0

12 = 3/4 * x
12 ÷ 3/4 = x
12 * 4/3 = x
48/3 = x
16 = x

Answer: The whole set is 16 counters

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$Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}$

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