This is what I got hope it helps!
Answer:
x = 16
m<Y = 34°
Step-by-step explanation:
∆XYZ is an isosceles ∆. An isosceles ∆ has two equal sides, as well as the bases of the isosceles triangle are congruent. In this case, therefore:
<X = <Z
(6x - 23)° = (4x + 9)
Solve for x
6x - 23 = 4x + 9
Collect like terms
6x - 4x = 23 + 9
2x = 32
Divide both sides by 2
x = 16
m<Y = 180° - (m<X + m<Z) (sum of ∆)
m<Y = 180 - ((6x - 23) + (4x + 9))
Plug in the value of x
m<Y = 180 - ((6(16) - 23) + (4(16) + 9))
m<Y = 180 - (73 + 73)
m<Y = 34°
First, coordinate Q is (-5,2) and Q' is (6,2). First, we know that this is a horizontal reflection becuase only the x-values change. This means that the line of reflection will be x=some value. I think the best way to go about this is to find the midpoint of Q and Q' using the formula: M=(x1+x2/2,y1+y2/2)
Q is the first point and Q' is the second point
M=(-5+6/2,2+2/2)
M=(1/2,4/2)
M=(1/2,2)
Since we know the y-values of Q, Q', and the midpoints are all 2, then the line of reflection would be x=1/2
Hope this helps
Regression line is given in the form of: y = a + bx
Where b is the gradient
Working out 'b'
Σxy - [ΣxΣy]/N
Σx² - [Σx]²/N
Working out 'a'
a = [∑y/N] - b[∑x/N]
a = [2650/460] - 0.264[3920/460]
a = 5.86 - 2.25
a = 3.61
Regression line equation is
y = 3.61 + 0.264x
