Area of ∆=1/2bh
80yd^2=1/2(b)(10yd)
80yd^2=5yd(b)
80yd^2÷5yd=b
16yd=b
Answer:
y=-8x-2
Step-by-step explanation:
The formula for slope is y2-y1/x2-x1. Take coordinate (0,-2), which is the y-intercept. We'll call that (y2,x2). Coordinate (8,-3) is (y1,x1). Put that into the formula you get, 0-8/-2-(-3). You get -8/1 which is negative 8. We now have the slope. Slope intercept form equation is y=mx+b. M is slope, so we put our slope in the equation and get, y=-8x+b. B is the y-intercept which is given. So we know that the equation to this line in slope-intercept form is y=-8x-2.
<h3>The area of the segment created by connecting the two points on the circle created by the angle described is 28.26 square centimeter</h3>
<em><u>Solution:</u></em>
Given that,
A central angle of a circle is 90 degrees
diameter of the circle is 12 cm
radius = 12/2 = 6 cm
To find: Area of segment
<em><u>The area of sector when angle is in degrees is:</u></em>

Where,
r is radius
is angle in degrees
Therefore,

Thus area of the segment created by connecting the two points on the circle created by the angle described is 28.26 square centimeter