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harina [27]
2 years ago
10

A coffee company ground up 547,736 coffee beans and distributed it evenly into 560 containers. How many coffee beans are in each

container?
Mathematics
2 answers:
weeeeeb [17]2 years ago
5 0
It is 978.1 per container I’m sure
pychu [463]2 years ago
5 0
The answer is 978.1
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In a bag of 18 oranges, 12 have gone bad.<br><br> What is the ratio of good oranges to bad oranges?
klemol [59]
Of 18 oranges, if 12 are bad that means 6 are good. Ratio of good to bad is 6:12 reduced to 1:2, the answer
4 0
3 years ago
If y=5x - 3 find the value of y when X = 0
madreJ [45]
Since we know y=5x - 3 and we know that x=0 then its a matter of plugging in what we know and simplifying. y=5 x 0 - 3 we need to remember the order of operations for this problem. PEMDAS parenthesis exponent multiply divide add subtrac. Since 5 time 0 is multiplication and multiplication comes before subtracting in the oder of operations we will solve that first. 5 times 0 equals 0 since anything times 0 is 0. All that's left is to subtract 3 which gives us y=-3 <span />
8 0
3 years ago
What is the relationship between the degree measure of the angle formed by the straight edges of a section of a circle graph as
Butoxors [25]

Answer:

  degree measure = 360° × percent of data

Step-by-step explanation:

The ratio of the degree measure of a sector of a circle graph to 360° is the same as the ratio of the represented data to the whole amount of data.

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The ratio of the central angle of the sector to 360° is the same as the percentage of data that sector represents.

7 0
3 years ago
2x + 4 / 3 = -8 please help
arsen [322]
X= -14/3 !


hope this helps
4 0
2 years ago
Read 2 more answers
A cyclist accelerates from 0 m/s to 8 m/s in 3 seconds. What is his acceleration? Is this acceleration higher than that of a car
77julia77 [94]

The average acceleration of an object is calculated as the final speed minus the initial speed divided by the elapsed time.

So:

a = \frac{V_f-V_0}{T_2-T_1}

Where

V_f= final speed

V_0 = initial speed

T_2-T_1 = elapsed time.

Thus:

The acceleration of the cyclist is:

a = \frac{8-0}{3}

a = 2.667m / s ^ 2

The acceleration of the car is:

a = \frac{30-0}{8}

a = 3.75 m/s^2

The average acceleration of the car is higher than the average acceleration of the cyclist.

7 0
3 years ago
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