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viktelen [127]
3 years ago
6

Are these correct? ILL MARKYOU AS BRAINLIEST

Mathematics
1 answer:
Soloha48 [4]3 years ago
3 0

Answer:

It definitely seems right, so you should be good!

<h2><u></u></h2><h2><u>Hope This Helped!</u></h2>

You might be interested in
What is 7285 divided by 4
serg [7]

Answer:

1821.25

Step-by-step explanation:

\frac{7285}{4} =  1821.25

5 0
2 years ago
Jordan spent 22% of his time doing math homework. If hw spent 11 minutes on his math homework. How many minutes did he spend on
Angelina_Jolie [31]

Jordan spends 50 minutes on his homework.

Step-by-step explanation:

Given,

Time spent on Maths homework = 11 minutes

This represents the 22% time of his total homework.

Let,

x be the total time spent on homework.

22% of x = 11

\frac{22}{100}*x=11\\0.22x=11

Dividing both sides by 0.22

\frac{0.22x}{0.22}=\frac{11}{0.22}\\x=50

Jordan spends 50 minutes on his homework.

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/1542444
  • brainly.com/question/1548911

#LearnwithBrainly

8 0
3 years ago
Please show your work. Find XY
Sidana [21]
XY = 17. 

Because YW is a perpendicular bisector, we can say that TW and WZ are both equal to 3. It tells us that XZ is 12, so that means that XW must be 12+3 which equals 15.

It also tells us that YW is 8. So we can use the Pythagorean Theorem to find the hypotenuse of Triangle XWY. Thus, 15^{2}  +  8^{2} =  XY^{2}

To solve this equation, square and add both of the terms on the right like this:
289 =  XY^{2}

And then take the square root of both sides. Your final answer should be: 
XY = 17. 
3 0
3 years ago
If you create a matrix, C, to show the inventory at the end of July, the value of the entry represented by C22 is ?
Inga [223]

Answer:

C_{22} = 389

Max(A_{31}) =376

Step-by-step explanation:

Given

See attachment for complete question

Solving (a): The entry C22

First, matrix C represents the inventory at the end of July.

The entry of C is calculated as:

C = Inventory - Sales

i.e.

C = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right]  -  \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]

C = \left[\begin{array}{ccc}543-102&356-78&643-97\\364-98&476-87&419-59\\376-54&903-89&409-79\end{array}\right]

C = \left[\begin{array}{ccc}441&278&546\\266&389&360\\322&814&330\end{array}\right]

Item C22 means the entry at the second row and the second column.

From the matrix

C_{22} = 389

Solving (b): The maximum A31 possible.

From the given data, we have:

Inventory = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right]

Unit\ Sales =   \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]

From the matrices above.

A31 means entry at the 3rd row and 1st column.

So, the possible values of A31 are:

A_{31} = 376

and

A_{31} = 54

By comparison, 376 > 54

So:

Max(A_{31}) =376  

8 0
2 years ago
I need help please ​
navik [9.2K]

Answer: B

Step-by-step explanation: the values start from zero to higher

4 0
2 years ago
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