(126) times (1/2 to the x/11 power) = 15% times 126
(1/2) to the x/11 power = 0.15
Take the log of both sides :
(x/11) times log(1/2) = log(0.15)
Multiply both sides by 11 :
'x' times log(1/2) = 11 x log(0.15)
Divide both sides by " log(1/2) " :
x = 11 x log(0.15)/log(1/2) = <em><u>30.107 years</u></em> (rounded)
That's the time it takes for <em><u>any-size</u></em> sample of this substance
to decay to 15% of its original size.
- m<1 = 145 | Supplementary
- m<3 = 35 | Vertical
- m<4 = 145 | Supplementary
- m<5 = 145 | (With Angle 4) If parallel then alternate interior angles congruent
- m<6 = 35 | (With Angle 5) Supplementary
- m<7 = 35 | (With Angle 6) Vertical
- m<8 = 145 | (With Angle 7) Supplementary
Hope it helps <3
(If it does, maybe brainliest :) Need one more for rank up)
<em>If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).</em>
<em>If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).</em>
81.1<u>3</u>9 ≈ <u>81.1</u>
Answer:
I will answer in a general way because the options are not given.
We know that the area of model A is smaller than the area of model B.
For model A, we have 72 shaded sections, out of 100.
Then the quotient of model A is:
72/100 = 0.72
For model B we have 10 sections, and x shaded ones.
Because model B is greater than model A, we know that:
x/10 should be larger than 72/100
then we have the inequality:
x/10 > 0.72
x > 0.72*10
x > 7.2
And we can not have more than 10 shaded sections (because there is a total of 10 sections) then:
10 ≥ x > 7.2
Then x can be any whole number in that interval.
the possible values of x are:
x = 8
x = 9
x = 10
