The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
8x^8/3 y^4 - The first option
Step-by-step explanation:
The first thing we need to do is the exponent outside the bracket and leave the 8 till last, because exponents always come before multiplying coefficients. When an term with an exponent is multiplied by another exponent outside a bracket, the exponents of both terms are multiplied by the exponent outside the bracket.
This means that the expression is now:
8(x^2*4/3 y^3*4/3)
First we can so the x term. The x term already has an exponent of 2, so the 2 is multiplied by the 4/3 exponent outside the bracket. 2*4/3 = 8/3, so the x term is now: x^8/3
The same happens to the y term: 3*4/3 simplifies to 4, so the y term is now y^4.
So now our expression is:
8(x^8/3 y^4)
Now the 8 outside the bracket simply multiplies on to the whole term so we finish with:
8x^8/3 y^4 - The first option.
Hope this helped!
Answer:
C. No, the image does not have the same orientation.
Step-by-step explanation:
Just took the quiz.
A= 1/2bh
fill in formula with known numbers
42= 1/2(7)h
multiply numerators on right side
42= (1*7)/2h
42= 7/2h
divide both sides by 7/2
42 ÷ 7/2= h
to divide fractions, multiply by reciprocal/inverse of 7/2
42 * 2/7= h
multiply numerators
(42 * 2)/7= h
84/7= h
12 inches= h
ANSWER: The height is 12 inches.
Hope this helps! :)
Answer:
2
Step-by-step explanation:
