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3 years ago

Please, What do you think of this. Please I need help on this

Mathematics

1 answer:

stich3 [128]3 years ago

8 0

Answer:

Step-by-step explanation:

Since Year 3 and 4 have the highest students just subtract 33-25 and you get 8

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Which one is the correct choice?

VARVARA [1.3K]

I don’t know man u should provide the choices also pls give me brainliest luv u

5 0

2 years ago

Read 2 more answers

Consider a TV set that consumes 120 W of electric power when it is on, and is kept on for an average of 6 h per day. For a unit

Andru [333]

The cost of electricity consumed by the TV per month is <u>$4.968</u>.

In the question, we are given that a TV set consumes 120W of electric power when switched on. It is kept on for a daily average of 6 hours per day. The number of days in the month is given to be 30 days. The cost per unit of electricity is 23 cents per kWh.

We are asked to find the cost of electricity the TV consumes in the month.

The daily energy consumed by the TV = Power*Daily time = 120*6 Wh = 720 Wh.

The monthly energy consumed by the TV = Daily energy*Number of days in the month = 720*30 Wh = 21600 Wh = 21600/1000 kWh = 21.6 kWh.

Hence, the total cost of electricity the TV consumes = Monthly energy*Per unit cost = 21.6*23 cents = 496.8 cents = $496.8/100 = $4.968.

Therefore, the cost of electricity consumed by the TV per month is <u>$4.968</u>.

Learn more about computing costs at

brainly.com/question/14277272

#SPJ4

3 0

2 years ago

Write the equation of the circle with the given center and radius.

34kurt

Step-by-step explanation:

The standard equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$

Center = (h, k)

Center = (0,2)

h = 0

k = 2

r = 5

$(x - h)^2 + (y - k)^2 = r^2$

$(x - 0)^2 + (y - 2)^2 = 5^2$

Center = (-4,-5)

h = -4

k = -5

r = $\sqrt{2}$

$(x - h)^2 + (y - k)^2 = r^2$

$(x - (-4))^2 + (y - (-5))^2 = \sqrt{2}^2$

$(x + 4))^2 + (y + 5))^2 = \sqrt{2}^2$

Center =(-1,3)

h = -1

k = 3

r = 8

$(x - h)^2 + (y - k)^2 = r^2$

$(x - (-1))^2 + (y - 3)^2 = 8^2$

$(x + 1)^2 + (y - 3)^2 = 8^2$

Center: (9,0)

h = 9

k = 0

r = $\sqrt{3}$

$(x - h)^2 + (y - k)^2 = r^2$

$(x - 9)^2 + (y - 0)^2 = \sqrt{3}^2$

4 0

3 years ago

Find the area of the shaded region

Alex777 [14]

∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

$\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm$

where $h$ is the length of the altitude originating from vertex O, and so

$\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm$

where $b$ is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

7 0

2 years ago

If (44)x = 432, what is the value of x

lana [24]

I think it's 108/11.. Pretty sure of it

7 0

3 years ago