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Pachacha [2.7K]
2 years ago
12

Given that y varies directly as x, and y= 27 when x = 54. Find the value of x when y = 54?

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
8 0
X equals 54 and y equals 27
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An overhead projector enlarges the image on its glass by a scale factor of 4. A rectangle that is 3 inches wide and 7 inches lon
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Just multiply the with and the length by four (considering the scale factor is 4)
3x4=12 and 7x4=28
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Find the work done by the force Bold Upper F equals xy Bold i plus (y minus x )Bold j over the straight line from (negative 1 co
aalyn [17]

Answer:

<h2>4/3 Joules </h2>

Step-by-step explanation:

Work is said to be done when force applied to an object causes the object to move through a distance.

Work done = Force * perpendicular distance.

\int\limits^a_b {F} \, ds

Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)

First we need to get the equation of the straight line given.

Given the slope intercept form y = mx+c

m is the slope

c is the intercept

m = y₂-y₁/x₂-x₁

m = 2-(-2)/1-(-1)

m = 4/2

m = 2

To get the slope we will substtutte any f the point and the slope into the formula y = mx+c

Using the point (1,2)

2 = 2+c

c = 0

y = 2x

Substituting y = 2x into the value of the force F = xy i + (y-x) j we will have;

F = x(2x) i + (2x - x) j

Using the coordinate (1, 2) as the value of s

W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) -  (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules

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3 years ago
The ages of the students in a dance class are 10, 9, 11, 12, 9, 10, 9, 10, 11, 12, 8, 12, 12.
faust18 [17]

Answer:

Put the numbers in order then find the number that appears the most which is 12.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASASP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!
Andre45 [30]
-5m - 6 >= 24
Add six on both sides
-5m >= 30
Divide by negative five on both sides
m >= -6
5 0
3 years ago
Read 2 more answers
1. In order to get more female customers, a new clothing store offers free gourmet coffee and pastry to its customers. The avera
ioda

Answer:

No, the manager is not correct based on the 95% confidence interval.

Step-by-step explanation:

We are given that the average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260, i.e.; X bar = $1080 and s = $260 and sample size, n = 35 .

The Pivotal quantity for 95% confidence interval is given by;

                \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = $1080

                s  = sample standard deviation = $260

                 n = sample size = 35 {five-week}

So, 95% confidence interval for average daily revenue, \mu is given by;

P(-2.032 < t_3_4 < 2.032) = 0.95

P(-2.032 < \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } < 2.032) = 0.95

P(-2.032 * {\frac{s}{\sqrt{n} } < {Xbar - \mu} < 2.032 * {\frac{s}{\sqrt{n} } ) = 0.95

P(X bar - 2.032 * {\frac{s}{\sqrt{n} } < \mu < X bar + 2.032 * {\frac{s}{\sqrt{n} } ) = 0.95

95% confidence interval for \mu = [ X bar - 2.032 * {\frac{s}{\sqrt{n} } , X bar + 2.032 * {\frac{s}{\sqrt{n} } ]

                                            = [ 1080 - 2.032 * {\frac{260}{\sqrt{35} } , 1080 + 2.032 * {\frac{260}{\sqrt{35} } ]

                                             = [ 990.70 , 1169.30 ]

<em>No, the manager is not correct based on the fact that the coffee and pastry strategy would lead to an average daily revenue of $1,200 because the calculate 95% confidence interval does not include value of $1200.</em>

Therefore, the store manager believe is not correct.

8 0
3 years ago
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