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Vaselesa [24]
2 years ago
12

What is the answer to 8^6÷8

Mathematics
2 answers:
Oliga [24]2 years ago
7 0
The answer to this equation is 8^5
Rus_ich [418]2 years ago
6 0

Answer:

32768

Step-by-step explanation:

8^6 is 262144

then divide 262144 by 8

so 262144 / 8 = 32768

Hope This Helped

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Select the correct answer.<br> Which function is the inverse of function<br> f(x) = -2
Artemon [7]

Answer:

B

Step-by-step explanation:

let f(x) = y and rearrange making x the subject

y = \frac{x+2}{7} ( multiply both sides by 7 to clear the fraction )

7y = x + 2 ( subtract 2 from both sides )

7y - 2 = x

Change y back into terms of x with x the inverse function, that is

p(x) = 7x - 2

8 0
2 years ago
Read 2 more answers
Q3. A bag contains 7 red balls and 3 green balls. A ball is taken out replaced.
ycow [4]

Part (a)

There are 7 red out of 7+3 = 10 total

<h3>Answer: 7/10</h3>

==========================================================

Part (b)

We have 3 green out of 10 total

<h3>Answer: 3/10</h3>

==========================================================

Part (c)

3/10 is the probability of getting green on any selection. This is because we put the first selection back (or it is replaced with an identical copy)

So (3/10)*(3/10) = 9/100 is the probability of getting two green in a row.

<h3>Answer: 9/100</h3>

==========================================================

Part (d)

Similar to part (c) we have 7/10 as the probability of getting red on each independent selection.

(7/10)*(7/10) = 49/100

<h3>Answer: 49/100</h3>

==========================================================

Part (e)

7/10 is the probability of getting red and 3/10 is the probability of getting green. Each selection is independent of any others.

(7/10)*(3/10) = 21/100

<h3>Answer: 21/100</h3>

==========================================================

Part (f)

We have the exact same set up as part (e). Notice how (7/10)*(3/10) is the same as (3/10)*(7/10).

<h3>Answer: 21/100</h3>
7 0
2 years ago
What is the value of the variable -38 = 2b + 25 - (-7b)
ddd [48]
The variable in this equation is b, therefore we have to calculate the value of b.

-38=2b+25-(-7b)
-38=2b+25+7b
2b+7b=-38-25
9b=-63
b=-63/9
b=-7

Answer: the value of the variable is b=-7

We can check it out this answer:
-38=2b+25-(-7b)
-38=2(-7)+25-(-7(-7))
-38=-14+25-49
-38=-38
4 0
3 years ago
How many eight-digit serial numbers contain three of one digit, two of another digit, two of yet another digit, and one of still
Harlamova29_29 [7]

It is easier to understand the problem if you create a number based on the criteria and then perform the computations. I am going to choose: 111 22 33 4

There are 10 options for the first "1" and only 1 option for the other two 1's

There are 9 remaining options for the first "2" and only 1 option for the other 2

There are 8 remaining options for the first "3" and only 1 option for the other 3

There are 7 remaining options for the "4"

10 x 1 x 1    x      9 x 1     x      8 x 1      x      7

10 x 9 x 8 x 7 = 5,040

Answer: 5,040

6 0
3 years ago
Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
Nat2105 [25]
By inspection, it's clear that the sequence must converge to \dfrac32 because

\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

when n is arbitrarily large.

Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}
\implies|2n-1|>\dfrac5{2\varepsilon}
\implies2n-1\dfrac5{2\varepsilon}
\implies n\dfrac12+\dfrac5{4\varepsilon}

As we're considering n\to\infty, we can omit the first inequality.

We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
6 0
3 years ago
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