3 years ago

What are the steps for substitution(word problems)? Please and thanks!

1 answer:

nataly862011 [7]3 years ago

6 0

The steps for substitution are step 1 solve for the equation x = or y then step 2 is substitute the solution from step 1 into the second equation and step 3 is solve the new equation for x.

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What is the solution to the equation A/2= -5

murzikaleks [220]

Answer:

A = -10

Step-by-step explanation:

A/2 = -5

Multiply both sides by the denominator of the fraction

We have A/2 x2 = -5 x 2

A = -10

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2 years ago

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Hi how your day going if it good and you have time then help me please

kherson [118]

Answer:

My day is going good so far

Anyways, the answer is 7 21/25

Step-by-step explanation:

4 + 8/5 + 8/5 + 16/25 =

4 + 16/5 + 16/25 =

4 + 80/25 + 16/25 =

4 + 96/25 =

4 + 3 + 21/25 =

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2 years ago

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horsena [70]

Answer:

whats the question

Step-by-step explanation:

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3 years ago

Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7

Firlakuza [10]

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

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2 years ago

0.8 times x is less than 0.6

suter [353]

False. Anything times 0.8 except 0, is 0.8 or more.

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2 years ago