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ivolga24 [154]
3 years ago
13

Use the sequence of operations to answer the question.

Mathematics
1 answer:
Blababa [14]3 years ago
3 0
11b. Is the answer. Okokok
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the length of a diagonal of a square field is 220 metres find the length of a side in metres and the area of the field in hectar
andre [41]

Answer:

Step-by-step explanation:

h^2=x^2+y^2, since this is a square x=y=s so

220^2=2s^2

2s^2=48400

s^2=24200

s=24200^(1/2)m (exact)

s=155.56m (rounded to nearest hundredth of a meter)

One hectare is equal to 10000m^2

A=24200m^2(h/10000m^2)

A=2.42 hectares

7 0
3 years ago
At the start of the month, Jodie had sold 885 copies of her new book. At the end of the month, she had sold 1,364 copies of her
ozzi

Approximately $ 31419 profit is earned from selling books in entire month

<em><u>Solution:</u></em>

Given that Jodie had sold 885 copies of her new book

At the end of the month, she had sold 1,364 copies of her book

We have to determine the profit earned in the entire month

From given information,

Start of month sale = 885 copies

End of month sale = 1364 copies

Total copies of books sold = Start of month sold + end of month sold

Total copies of books sold = 885 + 1364 = 2249

Also given that each book profit is $ 13.97

Profit of 1 book = $ 13.97

<em><u>Therefore for 2249 books, profit earned is given as:</u></em>

Profit of 2249 books = $ 13.97 x 2249 = 31418.53

Therefore approximately $ 31419 profit is earned from selling books in entire month

5 0
3 years ago
Mathematics, Due Today.
vovikov84 [41]
The first one is true
5 0
3 years ago
19.4mm what the lower bound correct to 1dp
padilas [110]

Answer:

The lower bound of 19.4 is 19.35

6 0
3 years ago
Evan wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn, so he needs no fence
pentagon [3]

Answer:  A.   A=(1000-2w)*w      B. 250 feet

C.  125 000 square feet

Step-by-step explanation:

The area of rectangular is A=l*w    (1)

From another hand the length of the fence is 2*w+l=1000        (2)

L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.

Express l from (2):

l=1000-2w

Substitude l in (1) by 1000-2w

A=(1000-2w)*w        (3)   ( Part A. is done !)

Part B.

To find the width w  (Wmax) that corresponds to max of area A   we have to dind the roots of equation (1000-2w)w=0  ( we get it from (3))

w1=0  1000-2*w2=0

w2=500

Wmax= (w1+w2)/2=(0+500)/2=250 feet

The width that maximize area A is Wmax=250 feet

Part C.   Using (3) and the value of Wmax=250 we can write the following:

A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets

3 0
3 years ago
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