Preyton took longer so he was slower. Now, we calculate the average speeds of both:
Preyton: 150 / 3 = 50 mph
Bryson: 150 / 2.5. = 60 mph
Therefore, Bryson travelled 10 mph faster than Preyton
Answer:

Step-by-step explanation:
m∠2 = 135° (Corresponding Angles)
m∠5 = 135° (Vertical Angles)
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AnonymousHelper1807</h3>
Answer:
Step-by-step explanation:
first term = a = 3
common ratio = 2nd term ÷ first term
= 12 ÷ 3
r = 4

Answer:
The distance between those points is 13.
Step-by-step explanation:
1. (x2-x1) = (-2 - -7) = 5
2. (y2-y1) = (-7 - 5) = -12
3. (5)2 + (-12)2 = 25 + 144 = 169
4. √169 = 13
5. 13