To build a triangle we need that the sum of any two given sides to be greater than the third side.
PQ+QR=
sqrt(58)+2sqrt(13)=14.82687566 >PR ✅
QR+PR=
2sqrt(13)+5sqrt(2)=14.28217036 >PQ✅
PQ+PR=
Sqrt(58)+5sqrt(2)=14.68684092>QR✅
So YES we can make a triangle with those dimensions
The least angle will be opposing the least side so will have
Angle PQR, angleQPR, angleQRP
Q
/\
/ \
P—— R
Answer:
Part A: One | Part B: x = 4
Step-by-step explanation:
500=350(1+0.04/12)^12x
Solve for x
500/350=(1+0.04/12)^12x
X=(Log(500/350)/log(1+0.04/12))/12
X=9 months
Answer:
x = 10
Step-by-step explanation:
the area of a square = s² ( s is the side length )
s² = (4x + 3)² ( take the square root of both sides )
s = = 4x + 3
perimeter = 4s = 172, that is
4(4x + 3) = 172 ( distribute left side )
16x + 12 = 172 ( subtract 12 from both sides )
16x = 160 ( divide both sides by 16 )
x = 10