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sukhopar [10]
3 years ago
5

If the range of f (x) = StartRoot m x EndRoot and the range of g (x) = m StartRoot x EndRoot are the same, which statement is tr

ue about the value of m? m can only equal 1. m can be any positive real number. m can be any negative real number. m can be any real number.
Mathematics
2 answers:
andriy [413]3 years ago
7 0

Answer:

The answer is B on EDGE 2020

Alona [7]3 years ago
4 0

Answer:B

Step-by-step explanation:

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13x=-21-6y and -8x=36+6y
IgorLugansk [536]

Answer:

x=3\\y=-10

Step-by-step explanation:

13x=-21-6y\\-8x=36+6y

Let's take one of the equations and solve for x. I'll take the first one.

13x=-21-6y

Divide by 13.

x=\frac{-21-6y}{13}

Now replace x in the second equation.

-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y

Distribute -8

\frac{168+48y}{13}=36+6y

Break down the fraction.

\frac{168}{13}+\frac{48}{13}y=36+6y

Subtract \frac{168}{13}

\frac{48}{13}y=36+6y-\frac{168}{13}

Subtract 6y

\frac{48}{13}y-6y=36-\frac{168}{13}

Combine like terms;

\frac{48-13*6}{13}y=\frac{36*13-168}{13}

Solve;

\frac{48-78}{13}y=\frac{468-168}{13}

Keep solving;

\frac{-30}{13}y=\frac{300}{13}

Multiply by the negative reciprocal of the fraction next to y.

(-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

y=-10

After having found y, replace it in any of the equations to find x.

13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3

6 0
3 years ago
Read 2 more answers
Select all the expressions that show the distance between points A and B.
qwelly [4]

Answer:

0 -1-(-8)

0-1=-1

-1-(-8)

-1+8

=7

7 0
3 years ago
Given that sin theta = 1/4, 0
GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

3) find cos(Θ)

This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

cos(Θ) = \sqrt{15} /4.

And that is the answer.
6 0
3 years ago
What is the equation of a circle with center (-4,7) radius 3?
miv72 [106K]

Answer:

a. (x + 4)² + (y – 7)² = 3²

Step-by-step explanation:

General equation for a circle is:

(x – h)² + (y – k)² = r²

h and k are the center (h, k), and r is the radius.

They want a center of (-4, 7) so h=-4 and k=7

They want a radius of 3 so r=3

plug it into the equation.

(x – h)² + (y – k)² = r²

(x – (-4))² + (y – (7))² = (3)²

(x + 4)² + (y – 7)² = 3²

7 0
3 years ago
Read 2 more answers
Hi can someone help me with the last two sets of shapes? Thank you so much! -Jenn
SOVA2 [1]
You are correct there's at least one obtuse angle
8 0
3 years ago
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