Answer:
1. -2
2. add 25/4
3. sub 25/2
4. 5/2
Step-by-step explanation:
Answer: 2
3
+
8
2
−
3
2
+
1
6
Step-by-step explanation:
Answer:
<h2>(6), -(-6)</h2>
Step-by-step explanation:
Answer:
ai) 73000 gal/yr
aii) $730 per year
b) 1000 days
Step-by-step explanation:
ai) The water usage per day is ...
(4 showers/day)(10 min/shower)(5 gal/min) = 200 gal/day
Then the usage per year is ...
(200 gal/day)(365 days/yr) = 73,000 gal/yr
__
aii) The cost of electricity is the cost of heating half the water usage, so is ...
(0.20 kWh/gal)(1/2)(73,000 gal/yr)($0.10/kWh) = $730/yr
__
b) The current daily cost of electricity for heating water is ...
($730/yr)/(365 days/yr) = $2/day
If the cost is cut in half, it will be $1 per day. That means the savings is $1 per day, so it will take 1000 days to recover the $1000 initial cost. (Effectively, the average cost for the first 1000 days is the same as if the water heater had not been replaced.)
Maybe from the equation of a line from y=mx+c
Where c ( intercept) is -12
