Answer:
put a down a point at (5,4) and go down 1 right 2, then plot another point.
You also can go from (5,4) up 1, left 2 and plot a point.
Please upload the figure too
Answer:
-3 or decreasing by 3
Step-by-step explanation:
To find the average change, you only care about the first and last point which would be (3,17) and (8,2)
the overall change during that time is 2-17=-15 (for the f(x) side )
the overall change during that time is 8-3=5(for the x side)
all we have to do is -15/5=-3
therefore the average rate of change is -3
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
