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eimsori [14]
3 years ago
15

Help please mathhhhh

Mathematics
1 answer:
Veronika [31]3 years ago
3 0

Answer:

Prime factors are factors of a number that are, themselves, prime numbers. There are many methods to find the prime factors of a number, but one of the most common is to use a prime factor tree. A prime number can only be divided by 1 or itself, so it cannot be factored any further with a factor tree.

Step-by-step explanation:

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Simplify<br> 3x^2+ 13x – 10<br> 9x^2 - 4
svetlana [45]

Answer:

                                The top one is (3x−2)(x+5)

the bottom one is    (3x−2)(3x+2)

Step-by-step explanation:

4 0
2 years ago
What is the value of x in the equation 8 + x = 3? (4 points) −5 5 11 24
Irina18 [472]

Answer:

-5 is the correct answer

8 0
3 years ago
Read 2 more answers
A farmer has 1,800 feet of fencing and wants to fence off a rectangular field that borders a straight river. he needs no fence a
astra-53 [7]
There are 2 short sides x and 1 long side y.

x+x+y=1,800
2x+y=1,800
y=1,800-2x

The area of the rectangle is A=x(1,800-x).


A is a function with variable x. Moreover it is a quadratic (second degree) function.

The graph of the function is a parabola which opens downwards, because the signs of the leading coefficients of the factors, multiply to minus:

(x)(-x)=-x^2.


This means that the highest point of the parabola, is its vertex V(h,k), so the function takes its largest value for x=h.


The roots of A=x(1,800-x) are x=0 and x=1,800, thus the x coordinate of the vertex, must be the midpoint of 0 and 1,800, that is 900.


Answer:

A=x(1,800-x)

largest area is when x=900

4 0
3 years ago
Read 2 more answers
1 (15 Points]. Prove the following statement: is divisible by 3 if only if it is a sum of three consecutive integers. be ddvisbk
Alinara [238K]

Answer:

<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.

Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:

n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).

So, n can be written as 3 times another integer, thus n is divisible by 3.

<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.

Assume that n is divisible by 3. The above proof suggest that we write it as

n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).

As k, k+1, k+2 are three consecutive integers, we have completed our goal.

Step-by-step explanation:

4 0
3 years ago
2.48030477 rounded to the nearest hundred-thousandth is
ValentinkaMS [17]
<span>2.48030, its rounded tenths 2.5  hundreths 2.48 thousands 2.480 ten-thousands 2.4803 then </span>hundred-thousandth 2.48030
3 0
3 years ago
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