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3 years ago

10

The number which is subtracted from a given number is called the

1 answer:

Anarel [89]3 years ago

5 0

Answer:

the subtrahend

I actually read it one time on wikipedia

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What are the zeros of the quadratic function y=x^2-100 when factoring?

Dovator [93]

Answer: zeros are 10 and negative 10

Step-by-step explanation:

(x-10) (x+10)

6 0

3 years ago

A train is booked to do the run between two places 55 km apart,in 1 hr 20 min. if it travels for the first 30 km at 36km per hou

soldier1979 [14.2K]

Answer:

<em>The train must travel at 50 km/hr to make it on time.</em>

<em></em>

Step-by-step explanation:

distance to be covered = 55 km

time to cover this distance = 1 hr 20 min

1 hr 20 min = 1.33 hrs (20 min = 20/60 hrs = 0.33 hrs)

The train travels the first 30 km distance at a speed of 36 km/hr

and we know that time taken = distance/speed

therefore the time taken to run this 30 km will be

time = 30/36 = 0.83 hr

The train still has 55 - 30 = 25 km to cover,

and the time left is 1.33 - 0.83 = 0.5 hrs left

to make it on time, the train must travel at

speed = distance/time = 25/0.5 = <em>50 km/hr</em>

6 0

3 years ago

if Andy's home is worth 260,000, what is his coverage for personal property if insurance covers 50 percent?

DiKsa [7]

$\frac{50*260000}{100}=130000$

5 0

3 years ago

Read 2 more answers

Please help me with these calculus bc questions

zhannawk [14.2K]

4. Compute the derivative.

$y = 2x^2 - x - 1 \implies \dfrac{dy}{dx} = 4x - 1$

Find when the gradient is 7.

$4x - 1 = 7 \implies 4x = 8 \implies x = 2$

Evaluate $y$ at this point.

$y = 2\cdot2^2-2-1 = 5$

The point we want is then (2, 5).

5. The curve crosses the $x$ -axis when $y=0$ . We have

$y = \dfrac{x - 4}x = 1 - \dfrac4x = 0 \implies \dfrac4x = 1 \implies x = 4$

Compute the derivative.

$y = 1 - \dfrac4x \implies \dfrac{dy}{dx} = -\dfrac4{x^2}$

At the point we want, the gradient is

$\dfrac{dy}{dx}\bigg|_{x=4} = -\dfrac4{4^2} = \boxed{-\dfrac14}$

6. The curve crosses the $y$ -axis when $x=0$ . Compute the derivative.

$\dfrac{dy}{dx} = 3x^2 - 4x + 5$

When $x=0$ , the gradient is

$\dfrac{dy}{dx}\bigg|_{x=0} = 3\cdot0^2 - 4\cdot0 + 5 = \boxed{5}$

7. Set $y=5$ and solve for $x$ . The curve and line meet when

$5 = 2x^2 + 7x - 4 \implies 2x^2 + 7x - 9 = (x - 1)(2x+9) = 0 \implies x=1 \text{ or } x = -\dfrac92$

Compute the derivative (for the curve) and evaluate it at these $x$ values.

$\dfrac{dy}{dx} = 4x + 7$

$\dfrac{dy}{dx}\bigg|_{x=1} = 4\cdot1+7 = \boxed{11}$

$\dfrac{dy}{dx}\bigg|_{x=-9/2} = 4\cdot\left(-\dfrac92\right)+7=\boxed{-11}$

8. Compute the derivative.

$y = ax^2 + bx \implies \dfrac{dy}{dx} = 2ax + b$

The gradient is 8 when $x=2$ , so

$2a\cdot2 + b = 8 \implies 4a + b = 8$

and the gradient is -10 when $x=-1$ , so

$2a\cdot(-1) + b = -10 \implies -2a + b = -10$

Solve for $a$ and $b$ . Eliminating $b$ , we have

$(4a + b) - (-2a + b) = 8 - (-10) \implies 6a = 18 \implies \boxed{a=3}$

so that

$4\cdot3+b = 8 \implies 12 + b = 8 \implies \boxed{b = -4}$ .

5 0

2 years ago

Please help..............................

r-ruslan [8.4K]

Volume of a sphere = (4/3)(pi)r^3
(4/3)(12.3)^3 = 2481.156 pi cm^3

7 0

4 years ago