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3 years ago

What is the length of line segment EB? 42 units 50 units 65 units 73 units

Mathematics

2 answers:

nignag [31]3 years ago

8 0

Answer:

Step-by-step explanation:

likoan [24]3 years ago

3 0

It 42 units hopes this helps

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Simplify 4.51 with a power of 0 4.51 1 0 −1

Bumek [7]

Answer:

Step-by-step explanation:

Remember that anything to the power of 0 is equal to 1

4.51^0 = 1

1 is your answer

8 0

3 years ago

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Determine the equation of the line that passes through the given points. (If you have a graphing calculator, you can use the tab

expeople1 [14]

You can write the equation in point-slope form, which has the format y-ysubscript1=m(x-xsubscript1), with ysubscript1 and xsubscript1 being the y and x coordinates for a point on the line, and m being the slope.

Substitute a y and x coordinate into the equation so you have y-6=m(x-2)

Then find the slope so you can replace m. The slope formula is (ysubscript2-ysubscript1)/(xsubscript2-xsubscript1). Substitute the coordinates in so you have m=(16-6)/(4-2), which simplifies to 10/2 and then 5.

Now the equation is y-6=5(x-2)

If you want a different form, for example slope-intercept form, you can change it to that:

y-6=5(x-2)

y=5x-4

6 0

3 years ago

Is 2 miles greater than or less than 3,333 yards

Lelu [443]

Greater! because 3,333 yards is about 1.8 miles.

4 0

3 years ago

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A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form

Over [174]

Answer:

$\vec{v}= \text{ or } \approx$

Step-by-step explanation:

Component form of a vector is given by $\vec{v}=$ , where $i$ represents change in x-value and $j$ represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector $\vec{v}=$ , the magnitude is $||v||=\sqrt{i^2+j^2$ .

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being $i$ , one leg being $j$ , and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

$\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}$

To find the other leg, $i$ , we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

$\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}$