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KiRa [710]
3 years ago
10

15-(4m - 5) = 32 please help me

Mathematics
2 answers:
atroni [7]3 years ago
7 0
The answer is = -3, hope this helps!
Sav [38]3 years ago
7 0

Answer:

m = -3

Step-by-step explanation:

15 - (4m - 5) = 32            (Given)

15 - 4m + 5 = 32             (Distributed)

20 - 4m = 32                  (Added like terms)

20 - 4m - 20 = 32 - 20  (Subtract 20 on both sides)

-4m = 12                         (Simplify)

-4m/-4 = 12/-4                (Divide -4 on both sides)

m = -3                             (Simplify)

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A mule dear can 1/4 of a mile in 25 seconds. At this rate, what expression can be used to determine how fast a mule deer runs in
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We have to find how many seconds are in one hour.
There are 60 seconds in one minute, with 60 minutes in every hour.
60×60=3600
Now, see how many 25 seconds are in 3600 seconds.
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Now, we can multiply 144 by 14 or .25 since we are trying to find per hour.
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3 years ago
5. Kamala worked for 7 1/2 h. She spent 2/3 of the time on her computer. How long was she on her computer?​
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Answer:

5 hrs

Step-by-step explanation:

7 1/2 hours equates to 450 minutes total

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2 years ago
Read 2 more answers
Solving multistep linear equations and inequalities<br>help me please​
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Step-by-step explanation:

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C = 10t + s

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30 + 8 = $38

5 0
3 years ago
Write the data from least to greater <br> $24, $44, $108, $36, $59, $71, $66
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Answer: $24, $36, $44, $59, $66, $71, $108

Step-by-step explanation:

3 0
3 years ago
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
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