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3 years ago

A service station charges $251 for

Mathematics

1 answer:

likoan [24]3 years ago

4 0

4x=251
251-84=167
4x=167
X=41.75
One tire will cost $41.75

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In a group of 60 students, 12 students take algebra one, 18 students take algebra 2 and 8 students take both subjects how many s

hoa [83]

60-12-18-2-8=20
=48-18-2-8
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So, 20 students don't take either of these subjects.

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3 years ago

Find the x and y intercept of 8x+10y=15. NO LINK TO ANSWER PLEASE TYPE

oee [108]

Answer:

x intercept: 15/8 and yintercerpt is 3/2

Step-by-step explanation:

to find y intercept you have to put equation in standard form.

10y=-8x+15

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x intercept is when y=0, so we plug in 0

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3 years ago

Evaluate 805 divide by 5

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A frost has caused a temporary spike in the price of orange juice. the price is now $10 a gallon. before the frost, the price wa

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3 years ago

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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

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3 years ago