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2 years ago

One evening, it snowed in several towns. The number of inches of snow the towns received are shown in the list below.

Mathematics

1 answer:

Rama09 [41]2 years ago

8 0

Answer:

3/4,3/4,3/4,3/4,1,1,2,11/2,11/2,11/4,11/4

Step-by-step explanation:

we just arrange the number from the smallest to bigger

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Stephanie has a total of 27 nickels and dimes. The total value of the coins is $1.95. Which system of equations can be used to f

Genrish500 [490]

The correct equation to use is A. n+d=27 0.05n+0.10d=1.95

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2 years ago

A wire 30 feet long is stretched from the top of a flagpole to the ground at a point 15 feet from the base of the pole. How high

sweet-ann [11.9K]

Answer:

28.3

Step-by-step explanation:

Use the Pythagorean Theorem to solve for the answer. 10^2 + x^2 = 30^2

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2 years ago

Read 2 more answers

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$