Answer:
1/3
Step-by-step explanation:
0.33* 3 is 99.9, which is as close to one hundred as possible
Answer:
Distributive Property.
Step-by-step explanation:
Cos(A-B)= Cos A- Cos B
The variables in the parenthesis gets multiplied into the Cos
Cos A - Cos B
Answer:
D. (4, 5)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = x + 1
y = 1/2x + 3
<u>Step 2: Solve for</u><u><em> x</em></u>
- Substitute in <em>y</em>: x + 1 = 1/2x + 3
- Subtract 1/2x on both sides: 1/2x + 1 = 3
- Subtract 1 on both sides: 1/2x = 2
- Divide both sides by 1/2: x = 4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x + 1
- Substitute in <em>x</em>: y = 4 + 1
- Add: y = 5
<u>Step 4: Graph</u>
<em>We can confirm our answer.</em>
Answer:
3150 feet for both
Step-by-step explanation:
correct?
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)