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Answer:
30 mph
Step-by-step explanation:
Let d = distance (in miles)
Let t = time (in hours)
Let v = average speed driving <u>to</u> the airport (in mph)
⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)
Using: distance = speed x time

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

Now all we have to do is solve the equation for v:







As v is positive, v = 30 only
So the average speed driving to the airport was 30 mph
(and the average speed driving from the airport was 45 mph)
Answer:
Base area = 36
Volume of the pyramid = 132
Step-by-step explanation:
Volume of a pyramid = Base Area × Height/3
Base area = Length × Length (since base of the pyramid is a square)
Given the side length of the square = 6
Base area = 6×6
Base area = 36
Given height of pyramid =11
Volume of the pyramid = 36×11/3
Volume of the pyramid = 12×11
Volume of the pyramid = 132
Answer:
1. 
2 a) 
b) 0
3. x = 10
Step-by-step explanation:
1.

2. a)
![2 [(\frac{-1}{4}) -12 (-1)^2] - 5[24 +2 (-12)]^2\\2[(\frac{-1}{4}) -12] - 5[24 -24]^2\\2 * [(\frac{-1}{4}) -12] -0\\\frac{-49}{2}](https://tex.z-dn.net/?f=2%20%5B%28%5Cfrac%7B-1%7D%7B4%7D%29%20-12%20%28-1%29%5E2%5D%20-%205%5B24%20%2B2%20%28-12%29%5D%5E2%5C%5C2%5B%28%5Cfrac%7B-1%7D%7B4%7D%29%20-12%5D%20-%205%5B24%20-24%5D%5E2%5C%5C2%20%2A%20%5B%28%5Cfrac%7B-1%7D%7B4%7D%29%20-12%5D%20%20-0%5C%5C%5Cfrac%7B-49%7D%7B2%7D)
b)

3.

1) Find x
The equation is:
4x=64
x=64/4=16
answer: x=16º
2)Find y:
The equation is:
(2y)+(3y+5)=180
5y=180-5
5y=175
y=175/5
y=35
Answer: y =35º
Find the measure of each angle...
3)∠a
2y+4x+a=180
2(35º)+4(16º)+a=180º
70º+64º+a=180º
a=180º-70º-64º=46º
Answer: ∠a=46º.
4)∠b
a+b=180º
46º+b=180º
b=180º-46º
b=134º
Answer: ∠b=134º
5)∠c
a+c=180º
46º+c=180º
c=180º-46º
c=134º
Answer: ∠c=134º
6)∠d
112º+d=180º
d=180º-112º
d=68º
Answer: ∠d=68º
7) ∠e
64º+d+e=180º
64º+68º+e=180º
e=180º-64º-68º
e=48º
Answer: ∠e=48º
8)∠f
e+f=180º
48º+f=180º
f=180º-48º
f=132º
Answer: ∠f=132º