Answer: 12 friends.
Step-by-step explanation:
the data we have is:
Mei Su had 80 coins.
She gave the coins to her friends, in such a way that every friend got a different number of coins, then we have that:
The maximum number of friends that could have coins is when:
friend 1 got 1 coin
friend 2 got 2 coins
friend 3 got 3 coins
friend N got N coins
in such a way that:
(1 + 2 + 3 + ... + N) ≥ 79
I use 79 because "she gave most of the coins", not all.
We want to find the maximum possible N.
Then let's calculate:
1 + 2 + 3 + 4 + 5 = 15
15 + 6 + 7 + 8 + 9 + 10 = 55
now we are close, lets add by one number:
55 + 11 = 66
66 + 12 = 78
now, we can not add more because we will have a number larger than 80.
Then we have N = 12
This means that the maximum number of friends is 12.
Use trigonometry.
sinQ = 14/50 = 0.28
-> angle Q = sin^-1(0.28) = approx 16 degrees
-> cosQ = A/H -> cos16 = PQ/50
=> PQ = 50*cos16 = approx 48.06
So yea.
Answer:
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- <u>No. You would have to cut the number of veggie burgers in more than half.</u>
Explanation:
<u>1. Model the situation with a system of equations</u>
<u />
<u>a) Name the variables:</u>
- number of turkey burgers: t
- number of veggie burgers: v
<u />
<u>b) Number of burgers:</u>
<u />
<u>c) Cost of the 50 burgers:</u>
<u>2. Solve that system of equations:</u>
<u />
<u>a) System</u>
<u>b) Mutliply the first equation by 2 and subtract the second equation</u>
- 100 = 2t + 2v
- 90 = 2t + 1.50v
- v = 20 ⇒ t = 50 - 20 = 30
<u />
<u>c) How much would you spend if the next year you buy the double of 20 turkey burgers (40) and the half of 30 veggie burgers (15)</u>
- $2(40) + $1.50(15) = $80 + $22.50 = $102.50
Then, you if you double the number of turkey burgers, and cut the number burgers in half, you would spend more than $90 ($102.50).
Step-by-step explanation:
I think this is correct and what you wanted
solution:
Attribute is not type of variable, instead, attributes are the categories of a categorical variable. For example: if variable is gender, attributes are male , female.
The number of robberies is not continuous because it connot take all values in a continuous interaval.
The number of robberies is quantitative because the value is numeric (discrete)
It is not qualitative because it is not nominal.
