2 years ago

6k^3+10k^2−56k and 5(7k−3)(3k−7)share a common binomial factor. What binomial factor do they share?

Mathematics

1 answer:

goldenfox [79]2 years ago

8 0

Answer:

Step-by-step explanation:

$6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)$

common factor is 3k-7

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Let's call the younger student's age A and the older student's age B. The teacher's age will be T.

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Simplify the last equation.

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Now we have two equations solved for T, so we can set them equal to each other.

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We can plug 2A in for B

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To find T, we plug 4 in for A in T = 5A + 20

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3 years ago

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sergiy2304 [10]

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