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ra1l [238]
3 years ago
7

Please help, test due in 1 hour! I will give brainliest! :)

Mathematics
2 answers:
Aleks [24]3 years ago
8 0

Answer:

A rectangular prism and half of a cylinder.

Step-by-step explanation:

The rectangular prism is for the bottom part, and if you cut a cylinder vertically down it's diameter, you would get the top shape. Put em both together and BAM you got a chest. Periodt.

Aleksandr-060686 [28]3 years ago
4 0

Answer:

Rectangle + half circle ?

Step-by-step explanation:

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What is 6/10 simplified
Komok [63]
6/10 = 3/5

Simply divide the numerator and denominator of 6/10 by 2. 6/10 is the same as 3/5.
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3 years ago
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Can you help me? Look at the last question I posted as an example.
ivolga24 [154]

Step-by-step explanation:

1. (-3/2, 1)

2. (6,-3)

3. (8/3, 2)

4. <u>(</u><u>2</u><u>,</u><u>-4</u><u>)</u>

<u>5</u><u>.</u><u>(</u><u>-3</u><u>,</u><u>-1</u><u>)</u>

<u>6</u><u>.</u><u> </u><u>(</u><u>0</u><u>,</u><u>3</u><u>/</u><u>2</u><u>)</u>

<u>7</u><u>.</u><u> </u><u>(</u><u>4</u><u>,</u><u> </u><u>-2</u><u>)</u>

<u>8</u><u>.</u><u>(</u><u>8</u><u>,</u><u>2</u><u>)</u>

<u>9</u><u>.</u><u> </u><u>(</u><u>0</u><u>,</u><u>0</u><u>)</u>

8 0
3 years ago
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The average cost of tuition plus room and board at small private liberal arts colleges is reported to be less than $18,500 per t
lys-0071 [83]

Answer:

The null and alternative hypothesis for this study are:

H_0: \mu=18500\\\\H_a:\mu< 18500

The null hypothesis is rejected (P-value=0.004).

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Then, the null and alternative hypothesis are:

H_0: \mu=18500\\\\H_a:\mu< 18500

The significance level is 0.05.

The sample has a size n=150.

The sample mean is M=18200.

The standard deviation of the population is known and has a value of σ=1400.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1400}{\sqrt{150}}=114.31

Then, we can calculate the z-statistic as:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{18200-18500}{114.31}=\dfrac{-300}{114.31}=-2.624

This test is a left-tailed test, so the P-value for this test is calculated as:

P-value=P(z

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

3 0
3 years ago
Solve for p: 6p + 6 = 13 + 5p
Ivan

Answer:

p equals 7

Step-by-step explanation:

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7 0
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Sever21 [200]

Answer:

1. $-50

2. $25

Step-by-step explanation:

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2.  If she deposits $75 in her account then it will be $75+(-50).  That translates to $75-$50 which is $25.  

+ and - = -

+ and + = +

- and - = +

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3 years ago
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