<span>Equation at the end of step 1 :</span><span> (((4•(a2))•b)-((8•(a3))•(b5)))+2ab7</span><span>Equation at the end of step 2 :</span><span><span> (((4•(a2))•b)-(23a3•b5))+2ab7
</span><span> Step 3 :</span></span><span>Equation at the end of step 3 :</span><span> ((22a2 • b) - 23a3b5) + 2ab7
</span><span>Step 4 :</span><span>Step 5 :</span>Pulling out like terms :
<span> 5.1 </span> Pull out like factors :
<span> -8a3b5 + 4a2b + 2ab7</span> = <span> -2ab • (4a2b4 - 2a - b6)</span>
Trying to factor a multi variable polynomial :
<span> 5.2 </span> Factoring <span> 4a2b4 - 2a - b6</span>
Try to factor this multi-variable trinomial using trial and error<span>
</span>Factorization fails
Final result :<span> -2ab • (4a2b4 - 2a - b6)
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<span>hope this helps hope i am brainliest i need it </span>
Answer:
3
Step-by-step explanation:
11-8=3
3 saves were left out of the 11 for the second game
Hi there!
The general equation of a slope-intercept line is :
y = mx + b
Where "m" is the slope and "b" is the y-intercept.
Since your equation is already in the right form, you can easily see that your "m" is equal to -4, which is the slope of the line.
Your answer is: The slope of the line is -4.
There you go! I really hope this helped, if there's anything just let me know! :)
If you use fractions, the answer you get will always be an exact answer in the form of a fraction. resorting to decimals means that you may run into rounding errors and therefore get only an approximate answer. e.g. the fraction 1/3 cannot be exactly represented by a decimal.fractions can be easier to represent the number rather then using decimals which involve writing out many numbers it does not affect the accuracy of the answer UNLESS you are rounding up and down the numbers
Answer:
Vertical angle=9.5°
Time to reach maximum height = 1.24seconds
Step-by-step explanation:
The maximum distance x is reached when rope swings to a maximum height, maximum height is gotten from the equation KE= 1/2MU^2 = MgH = MgL= Mgl(1- cos theta.
Where theta is the vertical angle, U=2m/s and L= 15m
2gl -2glcostheta=U^2
2gl U^2=2gl cos theta
But theta= Acos(1- U^2)/2gl
Acos(1-/(2×9.8×15)
Theta =9.5°
Maximum height li given by
Lsintheta
But X= UxT
T=X/UX= Lsintheta/U = 15sin9.5 /2 =1.24seconds
